Sagot :
Find the probability of the students that took the
calculus can be on the honor roll.
0.0035 => probability of students that take the AP Calculus
0.23 => probability of the students that can be on the honor roll
Let’s find the solution:
x = probability of the students that took the calculus can be on the honor roll.
=> x = 0.0035 / 0.23
=> 0.015
Thus, there is 0.015 probability that the students who took the AP Calculus can be on honor roll.
0.0035 => probability of students that take the AP Calculus
0.23 => probability of the students that can be on the honor roll
Let’s find the solution:
x = probability of the students that took the calculus can be on the honor roll.
=> x = 0.0035 / 0.23
=> 0.015
Thus, there is 0.015 probability that the students who took the AP Calculus can be on honor roll.
This is a question about conditional probability.
[tex]P(B|A) = \frac{P(AandB)}{P(A)}[/tex]
[tex]P(AP~calc|Honor~roll) = \frac{P(AP~calc~and~honor~roll)}{P(honor~roll)}= \frac{0.0035}{0.23}\approx0.015[/tex]
[tex]P(B|A) = \frac{P(AandB)}{P(A)}[/tex]
[tex]P(AP~calc|Honor~roll) = \frac{P(AP~calc~and~honor~roll)}{P(honor~roll)}= \frac{0.0035}{0.23}\approx0.015[/tex]