Sagot :
[tex] -2(x + 3) = -2(x + 1) - 4\\
-2x-6=-2x-2-4\\
-6=-6\\
x\in\mathbb{R}[/tex]
[tex]-2(x+3)=-2(x+1)-4\\\\-2x-6=-2x-2-4\\\\-2x-6=-2x-6\ \ \ \ |add\ (-2x)\ to\ both\ sides\\\\-6=-6\ \ TRUE\\\\
infinitely\ many\ solutions,\ x\in\mathbb{R}.[/tex]