Sagot :
[tex]\$6-the\ cost\ of\ buying\ candy\\\\2\times\$0.5=\$1-the\ cost\ of\ buying\ fudge\\\\\$6-\$1=\$5-the\ cost\ of\ buying\ caramels\\\\\$5:\$0.25=20-number\ bought \caramels\\\\Consuela\ has\ 10\ caramels,\ so\ Carrie\ has\ 20-10=10-caramels.[/tex]
Let the total number of caramel purchased = x
0.25x + ( 0.5 X 2 ) = 6$
0.25x + 1 = 6
0.25x = 6 - 1
0.25x = 5
Divide both sides by 0.25, we get
x = 20 ( Total no. of caramels )
So Total no. of candies = Caramel + Fudge = 20 + 2 = 22
Total caramel carrie receive = ( 20 - 10 ) = 10 caramel Answer
0.25x + ( 0.5 X 2 ) = 6$
0.25x + 1 = 6
0.25x = 6 - 1
0.25x = 5
Divide both sides by 0.25, we get
x = 20 ( Total no. of caramels )
So Total no. of candies = Caramel + Fudge = 20 + 2 = 22
Total caramel carrie receive = ( 20 - 10 ) = 10 caramel Answer