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What is the square root of 108 divided by the square root of 2q^6?? I really REALLY need the answer fast!

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[tex]\sqrt{108}:\sqrt{2q^6}=\sqrt{\frac{108}{2q^{3\times2}}}=\sqrt{\frac{54}{(q^3)^2}}=\sqrt{\frac{9\times6}{(q^3)^2}}=\frac{\sqrt{9\times6}}{\sqrt{(q^3)^2}}=\frac{\sqrt9\times\sqrt6}{q^3}=\frac{3\sqrt6}{q^3}[/tex]

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