Sagot :
Momentum = mass * velocity : p = mv
Time Rate of change of linear momentum of an object Δp / Δt
= Δ (m v ) / Δt = m Δv / Δt = m a
= Force acting on the object
= 40 Kg * 9 m /sec² = 360 Newtons
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Δ denotes change in a quantity. Δp = p2 - p1 Δt = t2 - t1
p2 = momentum at time t2 and p1 = momentum at time t1
v2 = velocity at time t2 v1 = velocity at time t1
a = acceleration, constant and same at t1 and t2
let u = velocity at time t = 0
Time rate of change of moment um is actually = (p2 - p1) / (t2 - t1)
p2 = m v2 p1 = m v1 So p2 - p1 = Δp = m (v2 - v1)
v2 = u + a t2 v1 = u + a t1 so, v2 - v1 = Δv = a (t2 - t1 ) = a Δt
So p2 - p1 = m (v2 - v1 ) = m a ( t2 - t1)
So ( p2 - p1 ) / (t2 - t1 ) = Δp / Δt = m a = 40 * 9 = 360 Newtons
Time Rate of change of linear momentum of an object Δp / Δt
= Δ (m v ) / Δt = m Δv / Δt = m a
= Force acting on the object
= 40 Kg * 9 m /sec² = 360 Newtons
==================================================
Δ denotes change in a quantity. Δp = p2 - p1 Δt = t2 - t1
p2 = momentum at time t2 and p1 = momentum at time t1
v2 = velocity at time t2 v1 = velocity at time t1
a = acceleration, constant and same at t1 and t2
let u = velocity at time t = 0
Time rate of change of moment um is actually = (p2 - p1) / (t2 - t1)
p2 = m v2 p1 = m v1 So p2 - p1 = Δp = m (v2 - v1)
v2 = u + a t2 v1 = u + a t1 so, v2 - v1 = Δv = a (t2 - t1 ) = a Δt
So p2 - p1 = m (v2 - v1 ) = m a ( t2 - t1)
So ( p2 - p1 ) / (t2 - t1 ) = Δp / Δt = m a = 40 * 9 = 360 Newtons
Momentum = (mass) x (speed)
Mass is constant, so the rate of change of momentum is
(mass) x (rate of change of speed) .
But (rate of change of speed ) is just acceleration.
So the rate of change of momentum is (mass) x (acceleration).
But (mass) x (acceleration) is Force.
So Force is the rate of change of momentum. Verrrrrrrry interesting !
In this problem, Force = (40 kg) x (9 m/s²) = 360 newtons.
One 'Newton' is one kilogram-meter per second² .
Unit of momentum is (kilogram)-(meter per second), so 'newton'
is also a unit of time rate of change of momentum.
Rate of change of momentum is 360 momentum units per second.
Mass is constant, so the rate of change of momentum is
(mass) x (rate of change of speed) .
But (rate of change of speed ) is just acceleration.
So the rate of change of momentum is (mass) x (acceleration).
But (mass) x (acceleration) is Force.
So Force is the rate of change of momentum. Verrrrrrrry interesting !
In this problem, Force = (40 kg) x (9 m/s²) = 360 newtons.
One 'Newton' is one kilogram-meter per second² .
Unit of momentum is (kilogram)-(meter per second), so 'newton'
is also a unit of time rate of change of momentum.
Rate of change of momentum is 360 momentum units per second.