Sagot :
First of all, you need to know how to find the area of a rectangle.
The area of a rectangle is (the length) multiplied by (the width).
You know that the length is 48 inches, and the width is 24 inches.
But before you run off and multiply those, look at the question again.
It asks for the area "... in square feet". If you just go and multiply
the (48 inches) by the (24 inches), you'll have the area in square inches.
You could do that, and then change square inches to square feet, but
I'm guessing that you don't know how to do that. So what will you do ?
Why not change the measurements to feet BEFORE you multiply them ? ! ?
You know that 1 foot is the same as 12 inches, right ?
So, 48 inches = 4 feet, and 24 inches is 2 feet.
The poster is 4-ft long by 2-ft wide. Multiply those: (4-ft) x (2-ft) = 8 square feet.
Is that neat or what !
The area of a rectangle is (the length) multiplied by (the width).
You know that the length is 48 inches, and the width is 24 inches.
But before you run off and multiply those, look at the question again.
It asks for the area "... in square feet". If you just go and multiply
the (48 inches) by the (24 inches), you'll have the area in square inches.
You could do that, and then change square inches to square feet, but
I'm guessing that you don't know how to do that. So what will you do ?
Why not change the measurements to feet BEFORE you multiply them ? ! ?
You know that 1 foot is the same as 12 inches, right ?
So, 48 inches = 4 feet, and 24 inches is 2 feet.
The poster is 4-ft long by 2-ft wide. Multiply those: (4-ft) x (2-ft) = 8 square feet.
Is that neat or what !
[tex]l=48in.\\w=24in.\\\\A_{\fbox{ }}=l\times w\Rightarrow A_{\fbox{ }}=48in\times24in=1152in^2\\\\1ft=12in\to1in=\frac{1}{12}ft\\\\ then:A_{\fbox{ }}=1152in^2=1152\times\left(\frac{1}{12}ft\right)^2=\left(1152\times\frac{1}{144}\right)ft^2=\boxed{8ft^2}[/tex]