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Jabary is thinking of 3 numbers the greatest number is twice as large as the least number the middle number is 3 more than the least number the sum of the 3 numbers is 75 find the numbers

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a + b +c = 75; where a is the greatest number; b is the middle number; c is the least number;

a = 2 * c;

b = 3 + c;

then, 2 * c + 3 + c + c = 75 => 4 * c = 72 => c = 72 / 4 => c = 18 => a = 2 * 18 => a = 36; b = 3 + 18 => b = 21;