Sagot :
Many many true statements could be offered regarding those two equations.
Sadly, until you share the list of choices you're looking at, there's no way for
anyone to help you choose the best one.
Sadly, until you share the list of choices you're looking at, there's no way for
anyone to help you choose the best one.
[tex]\begin{cases} 3x- \frac{1}{2}y=1 \ \ / \cdot 4\\ x+2y=7 \end{cases}\\\\\begin{cases} 12x- 2y=4 \\ x+2y=7 \end{cases}\\+ -------\\13x = 11\ \ / :13\\\\x=\frac{11}{13}[/tex]
[tex]x+2y=7 \\ \\ \frac{11}{13}+2y=7\\ \\2y=7-\frac{11}{13} \\ \\2y=\frac{91}{13}-\frac{11}{13}\\ \\2y =\frac{80}{13}\ \ / \cdot (\frac{1}{2})\\ \\y=\frac{40}{13} \\\\\begin{cases} x=\frac{11}{13}\\ y= \frac{40}{13} \end{cases} [/tex]
[tex]x+2y=7 \\ \\ \frac{11}{13}+2y=7\\ \\2y=7-\frac{11}{13} \\ \\2y=\frac{91}{13}-\frac{11}{13}\\ \\2y =\frac{80}{13}\ \ / \cdot (\frac{1}{2})\\ \\y=\frac{40}{13} \\\\\begin{cases} x=\frac{11}{13}\\ y= \frac{40}{13} \end{cases} [/tex]