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4x2+16x=0

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Iloveonedirectionid
[tex]4x^2+16x=0[/tex]

[tex] \frac{4x^2+16x}{4} =\frac{0}{4} [/tex]

[tex]x^2+4x=0[/tex]

[tex]x(x+4)=0[/tex]

[tex]x=0[/tex]

[tex]x+4=0[/tex]

[tex]x+4-4=0-4[/tex]

[tex]x=-4[/tex]


[tex]x=-4,0[/tex]
AL2006id
Divide each side of the equation by 4 :

x² + 4x = 0

Factor the left side:

x (x + 4) = 0

This equation is true if x=0 or if x=-4 , so those are the two solutions.

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