Sagot :
The volume of a cylinder with flat ends is (pi) x (radius squared) x (length) .
Radius of the tank = 1/2 diameter = d/2.
Volume = (pi) x (d/2)² x (height)
Height = ( V ) / ( pi x d²/4 )
Height = ( 4V ) / ( pi d² )
Radius of the tank = 1/2 diameter = d/2.
Volume = (pi) x (d/2)² x (height)
Height = ( V ) / ( pi x d²/4 )
Height = ( 4V ) / ( pi d² )
In this exercise we have to use the volume knowledge to calculate the size of the tank, like this:
[tex]H= ( 4V ) / ( \pi d^2)[/tex]
Then, recalling the formula for the volume of the cylinder, we find that:
[tex]volume= (\pi) * (radius \ squared) * (length)[/tex]
And we know some information like:
- Radius of the tank = 1/2
- diameter = d/2
In this way we find that:
[tex]Volume = (\pi) * (d/2)^2 * (height)\\Height = ( V ) / ( \pi * d^2/4 )\\Height = ( 4V ) / ( \pi d^2)[/tex]
See more about volume at brainly.com/question/1578538