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find the diagonal of a square with a perimeter of 28 inches

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AL2006id
Perimeter of a square = 4 x the length of one side = 28 in.
Length of one side = 7 in.
Length of the diagonal = square root of (7² + 7²) = 7√2 = 9.899 in (rounded)
[tex]a-side\ of\ square\\\\perimeter\ is\ 28in\\\\4a=28\ \ \ \ /:4\\a=7\ (in)\\\\The\ diagonal\ (d)\ equal\ a\sqrt2\\\\d=7\sqrt2\ inches.[/tex]

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