Answered

what is the value of root 12+root 12+root12....
...............to infinite

Sagot :

Ankursundaraid
x=root(12+root(12+root(...)))
x^2=12+root(12+root(12+root(...)))
x^2=12+x
x^2-x-12=0
(x+3)(x-4)=0
X=4