Sagot :
[tex]\left\{\begin{array}{ccc}y=2x-2\\y=-x+1\end{array}\right\\\\2x-2=-x+1\\2x+x=1+2\\3x=3\\x=1\\\\y=-1+1=0\\\\Solution:x=1;\ y=0[/tex]
If (2x-2) is equal to 'y', and (-x+1) is equal to 'y' then (2x-2) must be equal to (-x+1).
2x - 2 = -x + 1
Add 'x' to each side:
3x - 2 = 1
Add 2 to each side:
3x = 3
Divide each side by 3 :
x = 1
And then I guess y= 0 .
2x - 2 = -x + 1
Add 'x' to each side:
3x - 2 = 1
Add 2 to each side:
3x = 3
Divide each side by 3 :
x = 1
And then I guess y= 0 .