Sagot :
The line that's already there: -4x + 3y= 12
Add 4x to each side: 3y = 4x + 12
Divide each side by 3 : y = 4/3 x + 4
The line that's already there has a slope of 4/3.
Any line parallel to it has the same slope but different y-intercept.
If the new line passes through the origin, then its y-intercept is zero.
The equation of the new line is y = 4/3 x
Add 4x to each side: 3y = 4x + 12
Divide each side by 3 : y = 4/3 x + 4
The line that's already there has a slope of 4/3.
Any line parallel to it has the same slope but different y-intercept.
If the new line passes through the origin, then its y-intercept is zero.
The equation of the new line is y = 4/3 x
Slope of given line is m=-a/b =4/3
So searched equation is:
y-0=4/3(x-0)
y = 4/3x
So searched equation is:
y-0=4/3(x-0)
y = 4/3x