Jim has gotten scores of 99 and 93 on his first two tests. what score must he get on his third test to keep an average of 90 or greater

Sagot :

For the average to be 90,

(99 + 93 + x) / 3 = 90

or 192 + x = 270
or x = 270 - 192 = 78

Jim must score at least 78 in the third test.

Jim must get  ≥ 78 score to maintain his average  ≥ 90 .

What is an average ?

Every thing has a central tendency , Average is one of the measure of Central Tendency.

It is the mean of all the given numbers and is determined by summing all the numbers or data and then dividing by the total number of data.

It is given that

Jim has gotten scores of 99 and 93 on his first two tests.

He has to maintain an average of 90 or greater

The third test score = ?

Average = (99+93+x)/3

90≤ (99+93+x)/3

270 ≤ (99+93+x)

270 ≤ 192 + x

Therefore x ≥ 78

Jim must get  ≥ 78 score to maintain his average  ≥ 90 .

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