Iwise004id
Iwise004id
Mathematics
Answered
I need to find the zeros of the function:
f(x)=2x^2-5x-3
Sagot :
Konrad509id
Konrad509id
[tex]2x^2-5x-3=0\\ 2x^2-2x-3x-3=0\\ 2x(x+1)-3(x+1)=0\\ (2x-3)(x+1)=0\\ x=\frac{3}{2} \vee x=-1[/tex]
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