Sagot :
Put common terms in evidence and simplify:
[tex]\boxed{\frac{3x+9}{4x+12}=\frac{3(x+3)}{4(x+3)}=\frac{3}{4}}[/tex]
[tex]\boxed{\frac{3x+9}{4x+12}=\frac{3(x+3)}{4(x+3)}=\frac{3}{4}}[/tex]
[tex]
Answer :[/tex] [tex](3x+9)/(4x+12) \\ =3(x+3)/4(x+3) \\ =3/4 \\ (=0.75)[/tex]