Sagot :
[tex] 4x^2-17x-15=0\\
4x^2-20x+3x-15=0\\
4x(x-5)+3(x-5)=0\\
(4x+3)(x-5)=0\\
x=-\frac{3}{4} \vee x=5[/tex]
4x^2 - 17x - 15 = 0
(4x + 3)(x-5)
4x + 3 = 0
4x = -3
x = -3/4
x - 5 = 0
x = 5
(4x + 3)(x-5)
4x + 3 = 0
4x = -3
x = -3/4
x - 5 = 0
x = 5