Stacy05id
Stacy05id
English
Answered
Simply the expression : z2-z(z+3)+3z
Sagot :
Nicky442id
Nicky442id
This isn't English :) but :
z(z) becomes z^2 and -z (3) becomes -3z when you distribute.
z^2 -z^2 - 3z + 3z = z^2 - z^2 = 0
Answer Link
AL2006id
AL2006id
The part in the middle is -z(z + 3) becomes -z² - 3z .
Those two negative things cancel the two positive things in the expression . . .
well, here, let me show you :
z² - z(z + 3) + 3z =
z² [ - z² - 3z ] + 3z
. . . and that all adds up to exactly
zero
.
Answer Link
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