Aliciacdrama95id
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If a chemist analyzes a 3.84g sample containing sand and table sugar, and recovers 1.43g of      sand, what  percent by mass of table sugar should the chemist report for this sample.

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3.84 - 1.43 = 2.41
2.41g of table sugar

% mass = ( (mass of element) / (total mass) ) * 100
% mass = (2.41 / 3.84) * 100
% mass = (0.6276) * 100
% mass = 62.76

62.76%


well you would use the formula, which is,

mass percent= g of solute/ g of solute+ of solvent

and then you multiply by 100.....so when I did it I did 1.43/3.84+1.43 and multiplied it by 100 giving me 27%

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