Sagot :
Move all terms not containing x
from the center section of the interval inequality.
2−1<−x<6−1
Subtract 1 from 2 to get 1.
1<−x<6−1
Subtract 1 from 6 to get 5.
1<−x<5
Multiply each term in the inequality by −1.
1⋅−1>−x⋅−1>5⋅−1
Multiply 1 by −1 to get −1.
−1>−x⋅−1>5⋅−1
Multiply −x by −1 to get x.
−1>x>5⋅−1
Multiply 5 by −1 to get −5.
−1>x>−5
Rewrite the interval so that the left-hand value is less than the right-hand value. This is the correct way to write an interval solution.
−5<x<−1
Convert the inequality to set notation.
(−5,−1)
2−1<−x<6−1
Subtract 1 from 2 to get 1.
1<−x<6−1
Subtract 1 from 6 to get 5.
1<−x<5
Multiply each term in the inequality by −1.
1⋅−1>−x⋅−1>5⋅−1
Multiply 1 by −1 to get −1.
−1>−x⋅−1>5⋅−1
Multiply −x by −1 to get x.
−1>x>5⋅−1
Multiply 5 by −1 to get −5.
−1>x>−5
Rewrite the interval so that the left-hand value is less than the right-hand value. This is the correct way to write an interval solution.
−5<x<−1
Convert the inequality to set notation.
(−5,−1)
[tex]2 \leq 1 - x \leq 6\\
1\leq-x\leq5\\
-1\geq x\geq-5\\
x\in\langle-5,-1\rangle
[/tex]