Sagot :
[tex]f(x)=2x^3-x^2-5x+6 \ \ \ \boxed{x=2}\\
\\
f(2)=2*2^3-2^2-5*2+6\\
\\
f(2)=16-4-10+6\\
\\
f(2)=8[/tex]
Answer:
A Function states an equation that has only one answer for y for every x. Also, a function assigns exactly one output to each input of a specified type.
i,e y= f(x) where x represents the input variable and y represents the output value.
Given the function: [tex]F(x) = 2x^3-x^2-5x+6[/tex]
Substitute the given input value of x =2 , we get;
[tex]F(2) = 2(2)^3-(2)^2-5(2)+6[/tex]
[tex]F(2) = 2(8)-4-10+6[/tex]
or
[tex]F(2) = 16-4-10+6[/tex]
Simplify:
[tex]F(2) = 8[/tex]
Therefore, the function [tex]F(x)=2x^3-x^2-5x+6[/tex] for x=2, we have F(2) =8.