Sagot :
[tex]\frac{16}{14}=\frac{8}{7}=8:7-ratio\ of\ perimeters\\\\8^2:7^2=64:49-ratio\ of\ areas\\\\Answer:A.[/tex]
Answer:
A
Step-by-step explanation:
Two lengths of similar figures relates by the scale factor [tex]k[/tex].
Two areas of similar figures relates by the scale factor [tex]k^{2}[/tex].
- If length of one figure is A, and corresponding length of another figure is B, then they are related by:
[tex]A=kB[/tex]
- If area of one figure is A, and corresponding Area of another figure is B, then they are related by:
[tex]A=k^{2}B[/tex]
So we can write:
[tex]16=k(14)\\k=\frac{16}{14}=\frac{8}{7}[/tex]
Since, perimeter is also length, the ratio would be [tex]\frac{8}{7}[/tex]
Similarly, ratio of their areas should be [tex]\frac{8^2}{7^2}=\frac{64}{49}[/tex]
Answer choice A is right.