Sagot :
Delta = 25 - 16 = 9 => [tex] \sqrt{Delta} = 3;[/tex]
[tex] x_{1} = (-5 + 3)/4 = -1/2 and x_{2} = (-5 -3)/4 = -2;[/tex];
=> 2[tex] x^{2} + 5x + 2 = 2(x+1/2)(x+2).[/tex] = (2x+1)(x+2).
[tex] x_{1} = (-5 + 3)/4 = -1/2 and x_{2} = (-5 -3)/4 = -2;[/tex];
=> 2[tex] x^{2} + 5x + 2 = 2(x+1/2)(x+2).[/tex] = (2x+1)(x+2).
Answer:
(x + 2)(2x + 1)
Step-by-step explanation:
Hello!
We can factor this expression using the grouping method.
What is the Grouping Method?
The grouping method is a way to factor quadratic expressions and is mostly likely used when given an even number of terms. I will show you how to factor by grouping shortly.
Step 1: AC and B
This equation is written in the standard form of a quadratic : ax² + bx + c
The rule of grouping is that we need to find two factors, so that when the terms ax² and c are multipliedd together, the two factors would add to bx.
Using the given problem:
- ax² is 2x²
- bx is 5x
- c is 2
Multiply:
- 2(2x²)
- 4x²
That means that the two factors that multiply to 4x² should add to 5x. The terms that work is x and 4x.
Step 2: Expand and factor
Now we simply replace 4x and x for 5x.
- 2x² + x + 4x + 2
Now think of these one expressions as two seperate ones.
- (2x² + x) + (4x + 2)
Find the GCF in both parenthesis
- x(2x + 1) + 2(2x + 1)
Simplify
- (x + 2)(2x + 1)
Your factored equation is (x + 2)(2x + 1)