Sagot :
The answer to your question is: Yes.
Now, would you like to actually see the solution ?
First, multiply the quantity out:
(sin + cos)² = sin²(t) + cos²(t) + 2sin(t)cos(t)
You need to know:
==> sin²(any angle) + cos²(the same angle) = 1
==> 2sin(any angle)cos(the same angle) = sin(double the angle)
So the equation becomes:
(sin + cos)² = 1 + sin(2t)
Now, would you like to actually see the solution ?
First, multiply the quantity out:
(sin + cos)² = sin²(t) + cos²(t) + 2sin(t)cos(t)
You need to know:
==> sin²(any angle) + cos²(the same angle) = 1
==> 2sin(any angle)cos(the same angle) = sin(double the angle)
So the equation becomes:
(sin + cos)² = 1 + sin(2t)
[tex](sin\ t+cos\ t)^2=sin^2t+cos^2t+2\cdot sin\ t\cdot cos\ t=1+sin\ 2t[/tex]