Sagot :
density H2O = 1g/cm³
1,5 kg H2O = 1500g = 1500cm³ (1dm³ = 1000cm³)
3moles of NaCl-----in---------1500cm³ H2O
x moles of NaCl ----in--------1000cm³ H2O
x = 2moles of NaCl
answer: 2 mol/dm³
1,5 kg H2O = 1500g = 1500cm³ (1dm³ = 1000cm³)
3moles of NaCl-----in---------1500cm³ H2O
x moles of NaCl ----in--------1000cm³ H2O
x = 2moles of NaCl
answer: 2 mol/dm³
The molality of the sodium chloride solution is 2.0 mol/kg.
Given:
3.0 moles of NaCl in 1.5 kilograms of water.
To find:
The molality of the solution
Solution:
The moles of solute that is sodium chloride = 3.0 mol
The mass of solvent that is water = 1.5 kg
The molality of the solution:
[tex]=\frac{3.0 mol}{1.5 kg}=2.0 mol/kg[/tex]
The molality of the sodium chloride solution is 2.0 mol/kg.
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