Vregian77id
Vregian77id
Mathematics
Answered
(10y^3+20y^2+55y)/5y
Sagot :
Kyllieid
Kyllieid
( 10y^3 + 20y^2 +55y ) / 5y
= 2y^2 + 4y +11
And then depending on if the equation is set to zero in the problem, just factor or use the quadratic formula on the quadratic equation that is left.
Answer Link
Zainasayeed1id
Zainasayeed1id
Answer:
2y^2+4y+11
Step-by-step explanation:
Answer Link
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