There are 48 students in a school play. The ratio of boys to girls is 5:7. How many boys are in the school play? Explain how you found your answer

Sagot :

boys:  x
gilrs:   y

From the text of the task:

[tex] \left \{ {{\frac{x}{y}=\frac{5}{7}} \atop {x+y=48 \rightarrow x=48-y}} \right. [/tex]

Replacing x:

[tex]\frac{48-y}{y}=\frac{5}{7}\\ \\ 7(48-y)=5y\\ \\ 336-7y=5y\\ \\ 12y=336\\ \\ y=\frac{336}{12}=28[/tex]

So there are 28 girs and 20 boys
Did you say that the ratio of boys to girls is 5 to 7 ?

Well, then we know that 5 'groups' in the cast are boys, and 7 'groups' are girls.
So all together, there are 12 'groups' of students in the play, although we don't know
how many a 'group' is.

But wait a second.  You said there are 48 all together.  So each 'group' must be
48/12 = 4 students.

5 'groups' of boys = 20 boys
7 'groups' of girls = 28 girls

Check:

-- The ratio of 20 to 28 is 5 to 7 .  OK

-- 20 + 28 = 48 all together. OK

It all checks out.
yay