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Algebra 2 
Twice a number decreased by the cube of the same number

Sagot :

2(n)-n^2

Reorder in standard form: ax^2 + bx + c

-n^2 + 2n + 0

Answer:

2x-x^3

Step-by-step explanation:

It is x^3 because the question is asking for cube so don't use a root.

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