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solve this using substitution y=4x-8 and y=2x+10

Sagot :

[tex]\left\{\begin{array}{ccc}y=4x-8\\y=2x+10\end{array}\right\\\\4x-8=2x+10\\4x-2x=10+8\\2x=18\ \ \ /:2\\x=9\\\\y=4\cdot9-8=36-8=28\\\\Answer:x=9\ and\ y=28[/tex]