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The volume of 6.00M HCl needed to make 319 ml of 6.80M HCl

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The mole number of the solute after dilution is constant. So the mole number of 319 ml of 6.80 M HCl is 6.80*319*10^(-3)=2.17 mol. So the  volume of 6.00 M HCl needed is 2.17/6.00=0.362 L=362 ml.

Answer : The volume of 6.00 M HCl needed are, 361.5 ml

Solution :

According to the neutralization law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of HCl solution = 6.00 M

[tex]V_1[/tex] = volume of HCl solution = ?

[tex]M_2[/tex] = molarity of another HCl solution = 6.80 M

[tex]V_2[/tex] = volume of another HCl solution = 319 ml

Now put all the given values in the above law, we get the volume of HCl solution.

[tex](6.00M)\times V_1=(6.80M)\times (319ml)[/tex]

[tex]V_1=361.5ml[/tex]

Therefore, the volume of 6.00 M HCl needed are, 361.5 ml

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