At a certain temperature, 0.660 mol of SO3 is placed in a 3.00-L container.

2SO3(g) <---> 2SO2 + O2(g)

At equilibrium, 0.160 mol of O2 is present. Calculate Kc.

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Garnand16id Garnand16id

Chemistry

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At a certain temperature, 0.660 mol of SO3 is placed in a 3.00-L container.

2SO3(g) <---> 2SO2 + O2(g)

At equilibrium, 0.160 mol of O2 is present. Calculate Kc.

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Poppopularbee3id Poppopularbee3id · Answer 1

When this equilibrium shifts to the right, forming "X" mol of O2
2SO3(g) ---> 2SO2(g) + O2(g) 0.660 - 2X --> --> 2X & X since X = 0.130 this becomes 0.400 <=> 0.260 & 0.130 find moles / litre: (0.400) / 4.5L --> --> 0.260 / 4.5L & 0.130 / 4.5 L which gives these molarities: 2SO3(g) ---> 2SO2(g) + 1 O2(g) [0.08889] --> [0.05778] & [0.02889] Kc = [SO2]^2 [O2] / [SO3]^2 Kc = [0.05778]^2 [0.02889] / [0.08889]^2 Kc = (0.003338) [0.02889] / [(0.007901) Kc = 0.0122