Determine the empirical formula of the analysis of a compound being 9.2% B and 90.8% Cl

Question

Chemistry

Answered

Determine the empirical formula of the analysis of a compound being 9.2% B and 90.8% Cl

Sagot :

ID Other Questions

Which Of The Following Choices Was Not A Philosophy Contained In Thomas Paine's "Common Sense"? The Monarchy Is The Real Threat To Peace And Prosperity Of The C

Which Sentence Has A Misplaced Adjective Phrase? A. The First President Of The United States Was George Washington. B. Our Drive To Alabama Was Long. C. The

How Were The Governments Of Japan And Italy Similar In The 1930s? Check All That Apply. Both Were Headed By Groups Of Military Leaders. Both Used Extreme Nation

I’m Reading An Excerpt From “On The Revolutions Of The Heavenly Spheres” By Nicolaus Copernicus And It’s Just Explaining His Idea Of A Heliocentric Universe. Th

The Coordinates Of A Square Ar 1,8 7,8 7,2 ?,?

How Many Acts Does Macbeth Have

Please Can You Give Me Some Facts On Percentages Other Than How To Work Them Out???

• Prehistoric Indian Civilizations Created Them • Made Of Dirt By Hundreds Of Workers • Used For Different Purposes, Like Burying The Dead Or Building Sites For

Prior To The Passage Of The 25th Amendment, If A Vice President Left Office, __________. A. The President Would Appoint Someone To The Office B. Congress Would

• Prehistoric Indian Civilizations Created Them • Made Of Dirt By Hundreds Of Workers • Used For Different Purposes, Like Burying The Dead Or Building Sites For

Avbhandaid Avbhandaid · Answer 1

Let's begin by assuming that the mass of the molecule is 100 grams. This means that per 100 grams of molecule there are 90.8 grams of Chlorine, and 9.2 grams of Boron. Using the molar mass of each element we can find the number of moles of each element there are per 100 grams of molecule.

90.8 / 35.453 = ~ 2.56 moles of Chlorine
9.2 / 10.812 = ~ 0.851 moles of Boron
Now divide by the smallest mole number to find how many moles of each element there are in a 100 gram sample.
0.851/0.851 = 1
and 2.56/0.851 = ~3
Meaning that for every one mole of Boron there are 3 moles of Chlorine atoms
so the empirical formula is BCl3

Another way you can do this is by knowing that Boron has 3 valence electrons, and Chlorine has 1 meaning Boron can form 3 bonds with 3 different Chlorines, and that BCl3 is the simplest Boron Chlorine molecule.