Answered

the area of a rectangle is 54 cm. the length is 2 cm more than a x and the width is 5 cm less than twice of x. solve for x. round to the nearest whole number

Sagot :

Phaseripeid
A=54
xy=A=54
xy=54
x=2+n
y=2n-5
(2+n)(2n-5) = 54
2n^2-n-10 = 54
2n^2-n-64 = 0
Quadratic equation
(-2+-√(2²-4(2)(-64))/4
√4-512
√508
22.54
-2+- 22.54
        /4
5.13 or 6.135
so 5 or 6


ID Other Questions