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How many atoms are in 3.50 moles of calcium (Ca)?

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Marmalid
[tex]1\ mole\ --\ 6.02*10^{23}atoms\\ 3.5\ moles--x\\ x=21.07*10^{23}\ atoms[/tex]
Tadvisohil886id
No. of atoms = no.of moles x avagadro's constant

= 3.50 x 6.022*10^23

= 21.077 x 10 ^23

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