So,
#1: [tex]n \geq 3 \frac{11}{16} + 4 \frac{1}{2} [/tex]
Convert to like improper fractions.
[tex]n \geq \frac{59}{16} + \frac{72}{16} [/tex]
Add.
[tex]n \geq \frac{131}{16}\ or\ 8 \frac{3}{16} [/tex]
So, one solution could be [tex]8 \frac{3}{16} [/tex].
Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.
#2: [tex]k \ \textless \ 6 \frac{2}{5} * 15[/tex]
Convert into improper fraction form.
[tex]k \ \textless \ \frac{32}{5} * 15[/tex]
Multiply.
[tex] \frac{(2^5)(3)(5)}{5} [/tex]
Cross-cancel, and we have our final result.
[tex](2^5)(3) = 96[/tex]
k < 96
96 is not a solution.
95 is a solution.
So is 94, 93, 92, etc, and all numbers in between.
