Sagot :
A)
Because the greater the value if the co-efficient of x, the closer the graph is to the y axis ie: the narrower it is.
Because the greater the value if the co-efficient of x, the closer the graph is to the y axis ie: the narrower it is.
Answer:
The graph of 2x^2 is narrowest .
Step-by-step explanation:
A).y=2x^2
When plot the graph for y=2x^2
The graph of y=2x^2 is parabola and along positive y-axis.The graph passing through origin .We can see
Put x=0 Then we get
y=0
Hence, the parabola passing through origin.
When we put x=1 then we get
y=[tex]2\times 1=2[/tex]
Put x=2 we get
y=8
Put x=3 then we get
y=18
Hence, we can see as the value of x increases then the value of y increases very sharply.
B).y=[tex]\frac{1}{6} x^2[/tex]
The equation is also a equation of parabola
The parabola along positive y-axis.
Put x= 0 then we get
y=0
Hence, the parabola passing through the origin.
Put x=1 then we get
y= [tex]\frac{1}{6}[/tex]
Put x=2 then we get
y=[tex]\frac{2}{3}[/tex]
Put x= 3 then we get
y= 1.5
Hence, we can when x increases then value of y increases slowly in comparison to x.
C). y=[tex]-x^2[/tex]
The given equation is also a equation of parabola and along negative y- axis .
Putx=0 then we get
y=0
Hence, the parabola passing through the origin.
Put x=1 then we get
y= -1
Put x=2 then we get
y=-4
Put x=3 then we get
y=-9
Hence , value of y increases in direction of negtaive y-axis sharply in comparison to x increases .
D). y=[tex]\frac{1}{8} x^2[/tex]
The given equation is parabola and passing and along positive y- axis .
Put x=0 then we get
y=0
Hence, the equation of parabola passing through the origin.
Put x=1 then we get
y=[tex]\frac{1}{8}[/tex]
Put x= 2 then we get
y= [tex]\frac{1}{2}[/tex]
Put x=3 then we get
y= 1.125
Hence , we can see that value of y increases very slowly in comparison to x increases.