The number of atoms in a metal the product of weight of the atom of the metal and Avagardo's number divided by atomic mass.
- The number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.
- The number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.
- The magnitude of the charge of all these electrons is [tex]e=2.656\times10^{5}[/tex] C.
Given information-
The mass of the nickel coin is 5.7 g.
- A) The number of atoms in a nickel coin.
How to find number of atom in metal?
The number of atoms in a metal the product of weight of the atom of the metal and Avagardo's number divided by atomic mass.
As each mole (6.02 × 10^23 atoms) has a mass of about 57.9 g.
Thus the number of atom in a nickel coin with mass 5.7 kg,
[tex]n=\dfrac{5.7}{57.9} \times6.02\times 10^{23}[/tex]
[tex]n=5.93\times 10^{22}[/tex]
Hence the number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.
- B) Number of electrons in the coin.
As each nickel atom has 28 electrons/atom and total number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms. Thus number of electrons in the coin in nickel coin is,
[tex]q=5.93\times10^{22}\times28\\q=1.66\times 10^{24}[/tex]
Hence the number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.
- C) The magnitude of the charge of all these electrons-
Magnitude of the each electron, is [tex]1.6\times10^{-19}[/tex]. Thus the magnitude of the charge of all these electrons is,
[tex]e=1.66\times 10^{24}\times1.6\times10^{-19}\\e=2.656\times10^{5}[/tex]
Thus the magnitude of the charge of all these electrons is [tex]e=2.656\times10^{5}[/tex] C.
Hence,
- The number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.
- The number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.
- The magnitude of the charge of all these electrons is [tex]e=2.656\times10^{5}[/tex] C.
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