Sagot :
Well, the first 35 hours she works is $10 per hour.
[tex]35*10=350[/tex]
So that's 350 already.
Subtract 350 from 455.
[tex]455-350=105[/tex]
Our goal is to get 105.
After 35 hours, each hour after that she gets paid $15.
How many times can 15 go into 105?
[tex]105/15=7[/tex]
We're done!
Take the first 35 hours she worked and add the 7 we got from our last equation.
[tex]35+7=42\ hours[/tex]
She worked 42 hours to get $455 in one week.
[tex]35*10=350[/tex]
So that's 350 already.
Subtract 350 from 455.
[tex]455-350=105[/tex]
Our goal is to get 105.
After 35 hours, each hour after that she gets paid $15.
How many times can 15 go into 105?
[tex]105/15=7[/tex]
We're done!
Take the first 35 hours she worked and add the 7 we got from our last equation.
[tex]35+7=42\ hours[/tex]
She worked 42 hours to get $455 in one week.
well divide 435 by 10 so u can find if she worked 35 hrs.
43.5 hrs at $10 she did finish her $10 hours
455-350=105
105/15=15x/15
x=6
therefore she worked 35 hrs. +7 hrs.
she worked for 42 hours in total
43.5 hrs at $10 she did finish her $10 hours
455-350=105
105/15=15x/15
x=6
therefore she worked 35 hrs. +7 hrs.
she worked for 42 hours in total