Mjcheyid
Answered

How many combinations of 3 students can a teacher choose from 32 students?   A. 96   B. 4960   C. 29,760   D. 32,768


Sagot :

[tex]\frac{32*31*30}{3*2*1}[/tex]

The answer is:[tex]\frac{29760}{6}[/tex] or [tex]4960[/tex] 


Marmalid
[tex]{32\choose3}=\frac{32!}{3!*(32-3)!}=\frac{30*31*32}{6}=4960[/tex]