Sagot :
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2-3i+x+yi =6+0.i
2+x-i(3-y)=6+0.i
2+X=6
X=4
i(3-y)=0.i
Y=3
x+y.i
4+3i
2-3i+x+yi =6+0.i
2+x-i(3-y)=6+0.i
2+X=6
X=4
i(3-y)=0.i
Y=3
x+y.i
4+3i
Answer:
x + yi = 4 + 3i .
Step-by-step explanation:
Given : If (2 − 3i) + (x + yi) = 6,
To find : x + yi.
Solution : We have given that (2 − 3i) + (x + yi) = 6
We can rewrite the equation as
(2 − 3i) + (x + yi) = 6 + 0i
On removing parenthesis
2 − 3i + x + yi = 6 + 0i
On removing by 2 both sides
− 3i + x + yi = 6 - 2 + 0i.
− 3i + x + yi = 4 + 0i.
On adding 3i both sides
x + yi = 4 + 3i .
Therefore, x + yi = 4 + 3i .