Sagot :
It would looks like circle with radius of 3 and its center at (0,0).
Answer:
The coordinates (3,0), (-3,0), (0,3) ,and (0,-3) helps us to draw the graph of the circle. Below is the explanation
Step-by-step explanation:
Given:
The equation of a circle is [tex]x^{2} +y^{2} =9[/tex].
To find:
Graph the given equation.
Let's find the center and radius by comparing the given equation with the standard form.
[tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex]
We can rewrite our equation as [tex](x-0)^{2}+ (y-0)^{2}= 3^{2}[/tex]
Now, compare them
[tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex]
[tex](x-0)^{2}+ (y-0)^{2}= 3^{2}[/tex]
Center (h,k)=(0,0)
Radius r=3
Now, draw the graph of the circle by placing the center and radius.
So, the coordinates which are 3 units exactly from the center (0,0) help us to find the graph of the circle. So, (0,3), (0,-3), (3,0) ,and (-3,0) would help us to graph the circle.
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