Neil has a total of twelve $5 and $10 bills in his wallet. He has 5 times as many $10 bills as $5 dollar bills. How many of each does he have?

Sagot :

2 5 dollar bills
10 10 dollar bills

ammount of 5 dollar bills= x
amount of 10 dollar bills = y
5x=y
x+y=12

x+5x=12

6x=12

x=2

12-x=y

12-2=y

10=y 

There are two $5 bills and ten $10 bills in Neil's wallet and this can be determined by forming the linear equation in two variables.

Given :

  • Neil has a total of twelve $5 and $10 bills in his wallet.
  • Neil has 5 times as many $10 bills as $5 dollar bills.

Let the total number of $5 bills be 'a' and the total number of $10 bills be 'b'. Then the total number of bills will be:

[tex]a+b = 12[/tex]  --- (1)

It is given that Neil has 5 times as many $10 bills as $5 dollar bills, that is:

[tex]5a = b[/tex]  ---- (2)

Now, substitute the value of 'b' in equation (1).

a + 5a = 12

6a = 12

a = 2

Now, put the value of 'a' in equation (2).

[tex]5\times 2 = b[/tex]

b = 10

There are two $5 bills and ten $10 bills in Neil's wallet.

For more information, refer to the link given below:

https://brainly.com/question/13738061