John is 6 years older than Keisha. Together, their ages equal four times Keisha's age. How old is each? (Note: There must be an equation written using the variable x, and x must be solved.)

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John is 6 years older than Keisha. Together, their ages equal four times Keisha's age. How old is each? (Note: There must be an equation written using the variable x, and x must be solved.)

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Smartelephant026id Smartelephant026id · Answer 1

k= Keisha
k + 6= John
k + k + 6 = 4k
2k + 6 ( - 2k) = 4k ( - 2k)
6 = 2k
3 = k
(Keisha= 3 years old)
k + 6 = 9
(John = 9 years old)

3 + 3 + 6 = 4 (3)
12 = 12

So we made the pawn represent Keisha’s age. Then we knew that John is 6 years older than Keisha so we represented his age with a pawn plus 6. This went on 1 side of the equation because it said that together they equal 4 times Keisha’s age. So on the other side of the equation we put 4 pawns because we are using each pawn as Keisha’s age. Then we subtracted the pawns from each side to keep the equation balanced. So we had that 2 pawns equal 6, which means that each pawn equals 3 so Keisha is 3 years old. Since John is 6 years older than Keisha, he must be 9 years old. We checked our work and substituted 6 in for each pawn and found that 12 equals 12, so our equation is balanced.

Hope this helps :)

Cclemenoid Cclemenoid · Answer 2

Cclemenoid Cclemenoid

let x= Keisha
x+6= John
together means to add
x+x+6= 4x combine like terms
2x+6=4x
subtract 2x from both sides
6= 2x
divide both sides by 2
3=x Keisha's age
3+6= 9 John"s age

Proof 3+9= 4x3

hope this helps

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