Answer: The ball will land at 19.6 m
Explanation:
To calculate the horizontal range of the ball, we use the formula:
[tex]R=\frac{v^2\sin 2\theta}{g}[/tex]
where,
v = velocity of the ball = 14 m/s
[tex]\theta[/tex] = angle at which the ball is thrown = 51°
g = acceleration due to gravity = [tex]9.8m/s^2[/tex]
Putting values in above equation, we get:
[tex]R=\frac{(14)^2\times \sin (2\times 51)}{9.8}\\\\R=19.6m[/tex]
Hence, the ball will land at 19.6 m
