Sagot :
This is a common algebra problem. Let us start by establishing the numbers. By the way, here is the theory behind the math.
If we call the first number [tex]n[/tex], then the next consecutive even number is 2 away, so we will call it [tex]n+2[/tex], and so forth, the 3rd number [tex]n+4[/tex]
Lets form an equation! We know that given the sum of the 3 consecutive even numbers is 78, the equation is:
[tex]n+(n+2)+(n+4)=78[/tex]
Combine like terms, and we get:
[tex]3n+6=78[/tex]
Subtract 6 from both sides.
[tex]3n=72[/tex]
Divide both sides by 3, and we find our number to be:
[tex]n=24[/tex]
Hope this helped! Good luck.
If we call the first number [tex]n[/tex], then the next consecutive even number is 2 away, so we will call it [tex]n+2[/tex], and so forth, the 3rd number [tex]n+4[/tex]
Lets form an equation! We know that given the sum of the 3 consecutive even numbers is 78, the equation is:
[tex]n+(n+2)+(n+4)=78[/tex]
Combine like terms, and we get:
[tex]3n+6=78[/tex]
Subtract 6 from both sides.
[tex]3n=72[/tex]
Divide both sides by 3, and we find our number to be:
[tex]n=24[/tex]
Hope this helped! Good luck.
[tex]x+(x+2)+(x+4)=78\\3x+6=78\\3x=78-6\\3x=72\\
\\x= \frac{72}{3} \\
\\x=24[/tex]
The first number is 24
The first number is 24