A sports team is building a new stadium on a rectangular lot of land. If the lot measures 7x by 7x and the sports field will be 5x by 5x, how much of the lot will be left over to build bleachers on?

A. 4x²
B. 24x²
C. 74x²
D. 49x² - 25x²

Question

Mathematics

Answered

A sports team is building a new stadium on a rectangular lot of land. If the lot measures 7x by 7x and the sports field will be 5x by 5x, how much of the lot will be left over to build bleachers on?

A. 4x²
B. 24x²
C. 74x²
D. 49x² - 25x²

Sagot :

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JaySLid JaySLid · Answer 1

JaySLid JaySLid

7x*7x=49x^2, so the lot measures 49x^2.

The sports field, however, measures 5x*5x=25x^2.

The difference between these is 49x^2-25x^2=[tex]24x^2[/tex], or B.

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Panoyinid Panoyinid · Answer 2

Panoyinid Panoyinid

(7x · 7x) - (5x · 5x)
49x² - 25x²
24x²

It is equal to B.

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