Sagot :
So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.
You know that you have
90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle
sin19 = x/15
15sin19 = x
x = 2.2
Now do Pythagoras c^2-b^2=a^2
a = 14.8
So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)
You know that you have
90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle
sin19 = x/15
15sin19 = x
x = 2.2
Now do Pythagoras c^2-b^2=a^2
a = 14.8
So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)
Answer:
D. 4.9 units, 14.2 units
Step-by-step explanation:
By working in reverse, doing arctan( small side / big side) we can deduce it to answer D, seeing as
4.9/14.2 ~= 0.34507
[tex]tan^{-1}(0.34507) = 19.04degrees[/tex]
Which rounds out to 19degrees in the tenths.