Logderivativeid
Logderivativeid
Mathematics
Answered
find the derivative sinxln5x
Sagot :
Belcatyaid
Belcatyaid
sinxln5x=(sinx)'*ln5x+sinx*(ln5x)'=cosx*ln5x+sinx*[tex] \frac{1}{x} [/tex]=cosx*ln5x+[tex] \frac{sinx}{x} [/tex]
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