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Sagot :

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DF and AC are similar

and

BC and EF are similar sides

So make a proportion

[tex]\sf{ \frac{AC}{DF} = \frac{BC}{EF} }[/tex]

Plug in the numbers

[tex]\sf{ \frac{9}{DF} = \frac{15}{25} }[/tex]

Cross multiply

[tex]\sf{DF \times 15 = 9 \times 25}[/tex]

Isolate DF and simplify it

[tex]\sf{DF = 15}[/tex]

And so your final answer is

[tex]\boxed{\bf{15 ~centimeters}}[/tex]

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